Evaluate the following using suitable identit | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To evaluate $(102)^{3}$,we use the algebraic identity $(a+b)^{3} = a^{3} + b^{3} + 3ab(a+b)$.Here,we can write $102$ as $(100 + 2)$.Substituting $

Vedclass · Accepted Answer

$1061208$

Vedclass · Answer

(A) To evaluate $(102)^{3}$,we use the algebraic identity $(a+b)^{3} = a^{3} + b^{3} + 3ab(a+b)$.Here,we can write $102$ as $(100 + 2)$.Substituting $a = 100$ and $b = 2$ into the identity:$(100 + 2)^{3} = (100)^{3} + (2)^{3} + 3(100)(2)(100 + 2)$Calculating each term:$(100)^{3} = 1000000$$(2)^{3} = 8$$3(100)(2) = 600$Now,substitute these values back:$1000000 + 8 + 600(102)$$= 1000000 + 8 + 61200$$= 1061208$

Evaluate the following using suitable identities: $(102)^{3}$

Similar Questions

Find the remainder when $x^{3}+3x^{2}+3x+1$ is divided by $x+\pi$.

Factorise: $27x^3 + y^3 + z^3 - 9xyz$

Find the value of $k$,if $x - 1$ is a factor of $p(x)$ in this case: $p(x) = x^{2} + x + k$.

Factorise $x^{3}-23 x^{2}+142 x-120$

Factorise: $3x^{2}-x-4$

Vedclass Test Series

Exam Paper Generator

Online Exam Module